CivilFEM框架悬挑结构算例

文章目录

框架结构几何尺寸见下图：数据单位采用国际单位，梁柱尺寸(2 UAP 130/2 UAP 175/IPE 80)以及材料(Steel A42 -EA)均采用西班牙钢结构规范。分析内容包括：所有构件Y方向弯矩绝对值的最大值；构件X方向轴力绝对值最大值；在对弯矩和轴力考察的基础上，检查结构弯-压屈曲的情况，以及内力包络图分析，进行受力评价。荷载，分三阶段：自重+顶部均布荷载100N/m2 顶部雪荷载500N/m2 Y方向风荷载，施加到柱和顶部梁，600N/m2
FINISH ~CFCLEAR,,1 ! 总体数据 ! -------------------- /VUP,,Z /VIEW,1,1,1,1 ! CivilFEM SETUP ~UNITS,SI ~CODESEL,EC3,EC2,,,EC8 /PREP7 ! 2. Materials ! -------------------------------------------------- ~CFMP,1,LIB,STEEL,EA,A42 ! 3. Elements ! -------------------------------------------------- ET,1,44 ! BEAM44 ! 7. MODEL ! -------------------------------------------------- ! Nodes *AFUN,DEG A=TAN(5) *AFUN,RAD HP=2 L=3 WD=2.5 S=SQRT((L*A)**2+L**2) K,1,0,0,0 K,2,0,0,HP K,7,L,,HP+(L*A) KFILL,2,7,4, , ,1 KGEN,2,ALL, , , ,WD, ,7,0 ! Copy Kp ! Lines L,1,2 ! Column L,8,9 ! Column L,2,7 ! Horizontal beam L,9,14 ! Horizontal beam *DO,LINE,1,6 L,LINE+1,LINE+8 ! Transverse beams *ENDDO ! Components generation ! ------------------------- LSEL,S,,,1 $ LSEL,A,,,2 CM,Column,line ! Columns LSEL,S,,,3 $ LSEL,A,,,4 CM,Horizot,line ! Horizontal beams LSEL,S,,,5 ! Transverse beams *DO,I,6,10 LSEL,A,,,I *ENDDO CM,Transv,line ! 4. Sections ! -------------------------------------------------- ~SSECLIB,1,1,92,3 !2 UAP 130 ~SSECLIB,2,1,92,5 !2 UAP 175 ~SSECLIB,3,1,1,1 !IPE 80 ! 5. Beam & Shell Properties ! -------------------------------------------------- ~BMSHPRO,1,BEAM,1,1,,,44,1,0 ~BMSHPRO,2,BEAM,2,2,,,44,1,0 ~BMSHPRO,3,BEAM,3,3,,,44,1,0 ! 6. Member Properties (NECESSARY FOR CODE CHECKING) ! -------------------------------------------------------- !Columns Prop = 1 L = HP K = 0.6 KW = 0.5 C1 = 1.0 C2 = 0.0 C3 = 1.0 BETMY = 1 BETMZ = 1 BETMLT = 1 PSI = 0.8 LAT = 0 CFBXY = .75 CFBXZ = .75 CHCKAXIS = 1 ~MEMBPRO,Prop,EC3,ALL,L,K,KW,C1,C2,C3,BETMY,BETMZ,BETMLT,PSI,LAT,CFBXY,CFBXZ,CHCKAXIS !Horizontal beams Prop = 2 L = 3.0115 K = 0.85 KW = 0.5 C1 = 2 C2 = 0 C3 = 1 BETMY = 1 BETMZ = 1 BETMLT = 1 PSI = 0.8 AH = 0 LAT = 0 CFBXY = 1.5 CFBXZ = 1.5 CHKAXIS = 1 ~MEMBPRO,Prop,EC3,ALL,L,K,KW,C1,C2,C3,BETMY,BETMZ,BETMLT,PSI,LAT,CFBXY,CFBXZ,CHCKAXIS !Transverse beams Prop = 3 L = WD K = 1 KW = .5 C1 = 1.2 C2 = 1.2 C3 = 0 BETMY = 1 BETMZ = 1 BETMLT = 1 PSI = 0.8 AH = 0 LAT = 0 CFBXY = 1 CFBXZ = 1 CHKAXIS = 1 ~MEMBPRO,Prop,EC3,ALL,L,K,KW,C1,C2,C3,BETMY,BETMZ,BETMLT,PSI,LAT,CFBXY,CFBXZ,CHCKAXIS ! 5. Attributes & Mesh ! -------------------------------------------------- CMSEL,S,Column REAL,1 ESIZE,0.4 ! Elements of 0.4 m LMESH, all CMSEL,S,Horizot REAL,2 ESIZE,S/5 ! Elements of S/5 m LMESH, all CMSEL,S,Transv REAL,3 ESIZE,0.5 ! Elements of 0.5 m LMESH, all ALLSEL /ESHAPE,1 EPLOT NUMMRG,NODE,0.001, , ,LOW /SOLU ! Ansys Solution ! -------------------------------------------------- ! DOF restrains Dk,1, , , , , ,ALL Dk,8, , , , , ,ALL !Loads ! ----------- ! Self Weight ACEL,,,9.8 CMSEL,S,Transv CMSEL,A,Horizot ESLL,S Q=100 !100 (N/M2) SFBEAM,ALL,1,PRES,Q ALLSEL,ALL Solve ! Snow Load ACEL,,,, SFEDELE,ALL,ALL,PRES CMSEL,S,Transv CMSEL,A,Horizot ESLL,S S=550 !550 (N/M2) SFBEAM,ALL,1,PRES,S ALLSEL,ALL Solve !Wind in -Y direction SFEDELE,ALL,ALL,PRES W=600 CMSEL,S,Column LSEL,A,,,4 ESLL,S SFBEAM,ALL,2,PRES,W ALLSEL,ALL Solve ! CivilFEM Combinations ! --------------------------------------------------------------- /POST1 ! Clear previous combinations ~CMBCLR, ! Target definition ! --------------------------------------------------------------- ~TRGDEF,1,CROSS,M,Y,ABS ! Bending moment in Y ~TRGUPT,1,228,S,X ! Stress point definition ~TRGDEF,2,CROSS,SS,PT1,ABS ! Maximum stress ~TRGDEF,3,CROSS,F,X,ABS ! Axial force in X ! Combination No.1: /TITLE,Snow ! ~CMBDEF, ICMB, TYPE,NSTST ~CMBDEF, 1, ADDVC, 3 ! ~STSTDEF,ICMB,ISTST, TYPE ,ITEM1,ITEM2,ITIME,INCSTST,INCITEM1 ~STSTDEF, 1, 1,LSTEP,1 ! Self weight ~STSTDEF, 1, 2,LSTEP,2 ! Snow ~STSTDEF, 1, 3,LSTEP,3 ! Wind ! ~STSTDEF,ICMB,ISTST, CFT1, CFT2 ~STSTCFT, 1, 1, 1.35, 1.00 ! 1.33 or 1 *Self weight ~STSTCFT, 1, 2, 1.50, 0 ! 1.50 or 0 *Snow ~STSTCFT, 1, 3, 0.9, 0 ! (Fi*1.50)=0.9 or 0*Wind ! Combination No.2: /TITLE,Wind ! ~CMBDEF, ICMB, TYPE,NSTST ~CMBDEF, 2, ADDVC, 3 ! ~STSTDEF,ICMB,ISTST, TYPE ,ITEM1,ITEM2,ITIME,INCSTST,INCITEM1 ~STSTDEF, 2, 1,LSTEP,1 ! Self weight ~STSTDEF, 2, 2,LSTEP,2 ! Snow ~STSTDEF, 2, 3,LSTEP,3 ! Wind ! ~STSTDEF,ICMB,ISTST, CFT1, CFT2 ~STSTCFT, 2, 1, 1.35, 1.00 ! 1.33 or 1 *Self weight ~STSTCFT, 2, 2, 0.9, 0 ! (Fi*1.50)=0.9 or 0 *Snow ~STSTCFT, 2, 3, 1.50, 0 ! 1.50 or 0 *Wind ! Combination No.3: Envelope /TITLE,Envolvente ! ~CMBDEF, ICMB, TYPE ,NSTST ~CMBDEF, 3,OPTION, 2 ! ~STSTDEF,ICMB,ISTST, TYPE,ITEM1,ITEM2,ITIME,INCSTST,INCITEM1 ~STSTDEF, 3, 1,CMB, 1, , 2, 1, 1 ! Do combinations ! --------------------------------------------------------------- ~COMBINE, ! Point to combine results ~CMBDAT,2 ! Bending moments for combination 3, target 1(envelope) ~CFSET,,3,1 ~PLLSFOR,M,Y,-1 ! Stresses for combination 3, target 2(envelope) ~CFSET,,3,2 ~PLLSSTR,SX,ABS,-2 ! Axial load for combination 3, target 3(envelope) ~CFSET,,3,3 ~PLLSFOR,F,X,-1 ! Check for combination 3 (envelope) ~CFSET,,3,1 ~CHKSTL,BUCK_BCM,,full ! Compression+Bending Buckling ~PLLSSTL,ELM_OK ~PLLSSTL,crt_TOT ~CFSET,,3,3 ~CHKSTL,BUCK_BCM,,full ! Compression+Bending Buckling ~PLLSSTL,ELM_OK ~PLLSSTL,crt_TOT !Envelops ~ENVDEF,1,2 !1a and 2a alternatives ~ENVELOP,MAX ~CFSET,3 !Read 3th alternative ~PLLSSTL,ELM_OK ~PLLSSTL,crt_TOT
首先定义模型基本参数，包括：选择规范、定义材料、定义单元类型，创建模型几何形状；按照各个不同的荷载工况，分别进行加载、求解用~CMBCLR命令去除已经定义过的组合 ~TRGDEF：定义组合分析目标 ~CMBDEF：定义组合规则 ~STSTDEF：定义组合规则中的初始条件 ~STSTCFT：设置组合项目的分项系数进行荷载组合计算
- 结构钢截面检查 Lab1 由检查类型确定的Label ChckAxis 在求解弯矩、轴力等内力时用到的单元轴向. ClassMod 只在Eurocode 3中应用，定义力和弯矩的计算组 Value1 根据规范设定的数值举个例子，如果当前规范为欧洲规范，那么Lab1设为TENSION，则进行拉力检查；若为BENDING则为弯矩检查。
- 绘制钢结构梁计算结果，其中ELM_OK为显示结构中的构件是否通过检查，CRT_TOT为Total criterion ，NPLRD为截面的弹性强度等等。

这个实例是官方文档E05ENG.pdf中的第三个例子，在这一例中在多荷载工况的设置上，算是对前两个实例中介绍到的荷载组合做一定的总结。另外，在后处理中，介绍了屈曲分析的计算方法。由于CivilFEM是具有设计功能的专业软件，与ANSYS classic不同的是，它可以用简单的命令直接图形输出结构危险构件的位置和内力大小。